-2x^2+12x=-32

Solution for -2x^2+12x=-32 equation:

-2x^2+12x=-32

We move all terms to the left:

-2x^2+12x-(-32)=0

We add all the numbers together, and all the variables

-2x^2+12x+32=0

a = -2; b = 12; c = +32;
Δ = b2-4ac
Δ = 122-4·(-2)·32
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-20}{2*-2}=\frac{-32}{-4}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+20}{2*-2}=\frac{8}{-4}
=-2
$